The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
<h3>Quadratic equation</h3>
8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
- Using completing the square
8(x² + 2x + 1) = -3 + 8
8(x² + 1) = 5
(x² + 1) = 5/8
- Taking the square root of both sides
(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
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Sub in 5 for x
y=(5)2 -9
y= 10-9
y= 1
Answer:
Imperfect substitutes
explanation:
The choices above are not perfect substitutes, meaning they can not be perfectly or directly replace the other. Imperfect substitutes are close substitutes but not perfect substitutes. Unlike perfect substitutes, imperfect substitutes satisfies same utility but has different characteristics and therefore not entirely substitutable. For example, while one may want to have the 40 marks too, he'd rather have 60 marks even if the criteria for a 60 mark score was increasingly hard.
That equation means that John started with $107 in his bank account and is making $2 dollars a day. The correct equation is y=107x+2.
D.
When two countries are interdependent both countries can economically grow
