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Ainat [17]
4 years ago
5

VFind the difference between 7/ 10 and 1/ 5 . A) 1 10 B) 2 10 C) 3 10 D) 5 10

Mathematics
1 answer:
Law Incorporation [45]4 years ago
8 0

Answer:

Your answer is D.

Step-by-step explanation:

1. Take 1/5 and times it by 2:

2/10

2. Subtract 7/10 and 2/10:

7-2= 5

3. Keep the bottom number the same.

5/10

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Midpoint of the segment between the points (−5,13) and (6,4)
Leokris [45]

Answer: (0.5,8.5)

Step-by-step explanation:

We need to use the following formula to find the Midpoint "M":

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Given the points (-5,13) and (6,4) can identify that:

x_1=-5\\x_2=6\\\\y_1=13\\y_2=4

The final step is to substitute values into the formula.

Therefore, the midpoint of the segment between the points (-5,13) and (6,4) is:

M=(\frac{-5+6}{2},\frac{13+4}{2})\\\\M=(\frac{1}{2},\frac{17}{2})\\\\M=(0.5,8.5)

6 0
3 years ago
Read 2 more answers
What is not a problem modular division is used for?
Oksana_A [137]

Answer:

First let's define what modular arithmetic is, what would come is an arithmetic system for equivalence classes of whole numbers called congruence classes.

Now, the modular division is the division in modular arithmetic.

Answering the question, a modular division problem like ordinary arithmetic is not used, division by 0 is undefined. For example, 6/0 is not allowed. In modular arithmetic, not only 6/0 is not allowed, but 6/12 under module 6 is also not allowed. The reason is that 12 is congruent with 0 when the module is 6.

4 0
3 years ago
A support cable runs from the top of the telephone pole to a point on the ground 40 feet from its base. If the cable makes an an
kirill [66]
Okay, so this is just a bunch of random information that's eying to trick you. The answer is in the question. "the telephone pole to a point on the ground 40 feet from its base."
8 0
3 years ago
Please help me please answer it correctly
Kruka [31]

Answer:

$1,150

Step-by-step explanation:

<u>Step 1:  Find the total new members</u>

40 - 10

30 new members

<u>Step 2:  Add them to the total</u>

30 + 200

230 total members

<u>Step 3:  Find the money earned</u>

230 * 5

$1,150

Answer:  $1,150

8 0
3 years ago
Let W= { (x, y, z) |x=1|; y, z ∈ℝ } Prove that W is a subspace of ∈ℝ<br> How can I resolve this ?
Nataly [62]

Answer:

W is not a subspace.

Step-by-step explanation:

Notice that (-1,2,2) and (-1,5,3) are both elements of W. Because its x coordinate, x = -1, satisfy the condition |x| = 1.

but (-1,2,2) + (-1,5,3) = (-2,7,5) do not belongs to W. Because its first coordinate, x =-2, do not satisfy |x| = 1.  

5 0
3 years ago
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