Answer:
h(n+1) = h(n) - 7
Step-by-step explanation:
Our objective is to write the expression for h(n+1) in terms of h(n) which equals -31 -7(n-1)
So we use the given formula to find what h(n+1) is:
h(n+1) = -31 -7((n+1)-1)
h(n+1) = -31 -7(n+1-1)
we now re-arrange the order of terms inside the parenthesis without combining like terms:
h(n+1) = -31 -7(n-1+1)
and use distributive property to multiply "-7" times the "+1" term and get it extracted from inside the parenthesis:
h(n+1) = -31 -7(n-1) -7
Notice that this way we were able to preserve the form of the term h(n) "-31 -7(n-1)" , and see what is the modification introduced to it when finding the term h(n+1). We now replace "-31 -7(n-1)" by "h(n)" in the above equation:
h(n+1) = -31 -7(n-1) -7
h(n+1) = h(n) - 7
And this is the recursive formula that tells us how to construct the following term of a sequence by knowing the previous one.
Answer:
I think that the answer is 10
Answer:
The probability is 0.5438
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a. If 1 candy is randomly selected, find the probability that it weighs more than 0.8542g.
This is 1 subtracted by the pvalue of Z when X = 0.8542. So
has a pvalue of 0.4562
1 - 0.4562 = 0.5438
The probability is 0.5438
For 1lbs you will have to pay $15.50 so 4÷62=15.50 and also 8÷110=15.50
It would D because the slope is negative not positive