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maks197457 [2]
4 years ago
10

How many numbers equal 78? is this a stupid question? cause i think it is

Mathematics
2 answers:
kondaur [170]4 years ago
4 0
Well 78 only equals to 78, so that's just one number.

Unless you add or subtract two or more numbers together, there are millions of combinations
Dimas [21]4 years ago
4 0
1*78 2*39 3*26 6*13  
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lyudmila [28]
We have point P=(x_0,y_0)=(2,-4), so first calculate f'(x_0). There will be:

y=f(x)=2x^3-5x^2\\\\\\\\f'(x)=\big(2x^3-5x^2\big)'=\big(2x^3\big)'-\big(5x^2\big)'=2\big(x^3\big)'-5\big(x^2\big)'=\\\\=2\cdot3x^2-5\cdot2x=\boxed{6x^2-10x}\\\\\\\\f'(x_0)=f'(2)=6\cdot2^2-10\cdot2=6\cdot4-20=24-20=\boxed{4}

Now, we can write the equation of the normal line as:

y-y_0=-\dfrac{1}{f'(x_0)}(x-x_0)\\\\\\ y-(-4)=-\dfrac{1}{4}(x-2)\\\\\\y+4=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\\\y=-\dfrac{1}{4}x+\dfrac{1}{2}-4\\\\\\\boxed{y=-\dfrac{1}{4}x-\dfrac{7}{2}}

Normal line (and every line) crosses x-axis when y = 0, so coordinates of A:

\boxed{y=0}\qquad\qquad\text{and}\\\\\\y=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\&#10;0=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\\dfrac{1}{4}x=-\dfrac{7}{2}\quad|\cdot4\\\\\\x=-\dfrac{7\cdot4}{2}\\\\\\x=-7\cdot2\\\\\\\boxed{x=-14}\\\\\\\boxed{A=(-14,0)}
8 0
3 years ago
Solve for w<br><br> Simplify as much as possible <br><br> 3(3w-5)=12<br><br> plz help ty ;)
Masteriza [31]

Step-by-step explanation:

Simplifying

3(3w + -5) = 12

Reorder the terms:

3(-5 + 3w) = 12

(-5 * 3 + 3w * 3) = 12

(-15 + 9w) = 12

Solving

-15 + 9w = 12

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '15' to each side of the equation.

-15 + 15 + 9w = 12 + 15

Combine like terms: -15 + 15 = 0

0 + 9w = 12 + 15

9w = 12 + 15

Combine like terms: 12 + 15 = 27

9w = 27

Divide each side by '9'.

w = 3

Simplifying

w = 3

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Answer:

What do you mean?

Step-by-step explanation:

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I believe it should be $31,500
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