Answer:
The Answer is: y - 3 = 3/2(x - 1)
Step-by-step explanation:
Given Points: (1, 3) and (-3, -3)
Find the slope m:
m = y - y1 / (x - x1)
m = 3 - (-3) / (1 - (-3))
m = 3 + 3 / 1 + 3
m = 6 / 4 = 3/2
Use the point slope form and point (1, 3):
y - y1 = m(x - x1)
y - 3 = 3/2(x - 1)
Hope this helps! Have an Awesome day!! :-)
Answer:
reflection over the x-axis
Step-by-step explanation:
i hope this helps
Answer:
It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.
Step-by-step explanation:
Micheal runs 3 miles in one hour or 60 minutes.
In one minute he runs 3/60= 1/20 or 0.05miles.
Jack runs 4.5 miles in one hour or 60 minutes.
In one minute he runs 4.5/60= 45/600= 9/120= 3/40 or 0.075 miles.
So Jack is 0.075/0.05 = 1.5 times faster than Micheal.
or Micheal is 1.5 times slower than Jack.
Jack starts from 2:20 pm and at 3 pm he will run 0.075(40 minutes)= 3miles
Micheal start at 2:00 pm and at 3 pm he will run 0.05(60 minutes)= 3 miles
So at 3 pm both will have covered equal distance= 3miles.
It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.
Answer:
w = -1.266
Step-by-step explanation:
distribute the 5 by everything in the parenthesis and then bring everyhting down then you should have a regular equation to work w
Answer:
The time taken for the flare to hit the ground is approximately 10.7 seconds.
Step-by-step explanation:
Given : Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation
models the h height at t seconds of the flare.
To find : How long will it take for the flare to hit the ground?
Solution :
The equation
models the h height at t seconds of the flare.
The flare to hit the ground when h=0.
Substitute in the equation,

Applying quadratic formula, 
Where, a=-16, b=160 and c=120





Reject the negative value.
Therefore, the time taken for the flare to hit the ground is approximately 10.7 seconds.