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bazaltina [42]
1 year ago
9

14. Solve the equation using the Zero Product Property

Mathematics
1 answer:
Alekssandra [29.7K]1 year ago
3 0

Answer:

14) D; 16) C.

Step-by-step explanation:

14) the given equation can be written (x-2)(x-1/2)=0;

D. -2; 1/2.

16. if the original length is 'x', then it is possible to make up the equation of area:

(x+3)²=225; ⇒ x=12;-18; x=12 [m], the C option.

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Answer:

The equation of the line is y=4/3x+1

Step-by-step explanation:

I don't know the statement.

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2 years ago
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Which property will Sarah use to solve 6x = 42?
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Answer:

multiplication property of equality

Step-by-step explanation:

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3 years ago
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g The probability that a university graduate will be offered no jobs within a month of graduation is estimated to be 5%. The pro
dexar [7]

Answer:

49% probability that a graduate is offered fewer than two jobs

Step-by-step explanation:

We have these following probabilities:

5% probabilities of not being offered a job

44% probability of receiving one job offer

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23% probability of receiving three job offers.

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49% probability that a graduate is offered fewer than two jobs

8 0
2 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
2 years ago
Honon spent 3 hours on homework yesterday while Sequoia spent
Papessa [141]

Answer:

1 hour

Step-by-step explanation:

it asks you

<em>How much more time did Honon spend on homework than</em>

<em>Sequoia?? </em>

so it's 3 hours- 2 hours

= 1 hour

3 0
3 years ago
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