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Ierofanga [76]
2 years ago
8

A 14 foot ladder is leaning against a building. The ladder makes a 45 degree angle with the building. How far up the building do

es the ladder reach?
Mathematics
1 answer:
3241004551 [841]2 years ago
5 0
Sin 45 = X / 14
X = 14 * sin45
X = 7√2≈9.89949
Thus ladder will reach to ≈ 9.9 (rouded-up) foot height in the building
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4 + 6^2 + 9 ∙ 3 - 10
Korvikt [17]
4+6^2+9•3-10

PEMDAS
P=parentheses
E=exponent
m=multiplication
d=division
a=addition
s=subtraction

*no parentheses in this equation
*exponent = 6^2
6^2=36
4+36+9•3-10
*multiplication = 9•3
9•3=27
4+36+27-10
*addition=4+36+27
4+36+27=67
67-10
*subtraction=67-10
67=10=57

ANSWER=57







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