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3 years ago

14

How do you find the slope of a line on a graph?

1 answer:

harina [27]3 years ago

5 0

Find two points on the graph.
example: (1,2) and (3,4)
Using the equation, $\frac{y2-y1}{x2-x1}$ ,will give you the answer.
so for the example, if you plug in the numbers, you get (mobile) 1/3 $\frac{1}{3}$

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Suppose f(x)=x^2 what is the graph of g(x)= f(5x)

Novosadov [1.4K]

Answer:

Step-by-step explanation:

That '5' in f(5x) will compress the graph of x^2 horizontally.

If you were to graph f(x) = x^2, you'd get a parabolic graph; the parabola will open UP.

Suppose you graphed f(x) = x^2 on the interval [-4, 4].

Then the graph of g(x) = f(5x) would be graphed on the interval [-4/5, 4/5]. In other words, the graph would be on a shorter interval, one shorter by a factor of 5.

6 0

3 years ago

Read 2 more answers

Sketch the graph of = 3 on the axes below:

Aneli [31]

The graph should look the the one I attached to this answer

7 0

3 years ago

What is the square root of 29,

sweet [91]

Nothing times itself will equal 29, but in decimal form only is 5.38

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3 years ago

Word form for571082346090

Pie

571,082,346,090 in word form would be Five hundred seventy one billion eighty two million three hundred forty six thousand ninety.

7 0

3 years ago

Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam

kompoz [17]

For this case, we perform the conversions:

First roll:

$1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x$

$x = \frac {3 * 100} {1}\\x = 300 \ meters.$

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

$c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71$

You can pack 71 boxes.

Second roll:

$1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.$

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

$c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16$

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

$c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11$

You can pack 11 boxes.

Thus, in total you can pack $11 + 16 + 71 = 98 \ boxes$

Answer:

98 boxes

4 0

3 years ago