Answer: 216
Step-by-step explanation:
I am gonna go for D is the answer.
Answer:
The formula for this quadratic function is x*2 +6x+13
Step-by-step explanation:
If we have the vertex and one point of a parabola it is possible to find the quadratic function by the use of this
y= a (x-h)*2 + K
Quadratic function looks like this
y= ax*2 + bx + c
So let's find the a
y= a (x-h)*2 + K where
y is 13, x is 0, h is -3 and K is 4
13= a (0-(-3))*2 +4
13=9a +4
9=9a
9/9=a
1=a
The quadratic function will be
y= 1(x+3)*2 + 4
Let's get the classic form
(x+3)*2 = (x+3)(x+3)
(x*2+3x+3x+9)
x*2 +6x+13
f(0) = 13
Answer:
18 units
Step-by-step explanation:
If you draw lines from the corner points (L, E, J, and P) to the center, you will find that they bisect the corner angles. For the lines to be tangent, LU=LK, PU=PV, JV=JS, and ES=EK.
Perimeter=LK+KE+ES+SJ+JV+VP+PU+UL
Since LU=LK=4, PU=PV=1, JV=JS=2, and ES=EK=2
Perimeter=4+2+2+2+2+1+1+4
Perimeter=18
Answer: the 4th/last option
Step-by-step explanation:
Y goes up when x goes down or up. When x = 0, y = 2
