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musickatia [10]
3 years ago
11

A rectangular piece of metal is 30 in longer than it is wide. Squares with sides 6 in long are cut from the four corners and the

flaps are folded upward to form an open box. If the volume of the box is 3354 incubed​, what were the original dimensions of the piece of​ metal?

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer = 55,25 inches

Solution -

let's take x as length and y as width of the metal piece. As per the question x is 30 more than y,

⇒ x = y + 30

Then four square pieces of side 6 are cut from each corner,

so the new length and width are

x-12 , y-12

Then the volume of the new box created will be

(x-12)(y-12)6

in the question the volume of the given figure is given to be 3354

so (x-12)(y-12)6 = 3354

putting the value of x in the the above equation

⇒ (y+30 - 12)(x-12) = 3354/6 = 559

⇒ (y+18)(y-12) = 559

⇒ y² + 6y - 775 = 0

⇒ y² + 31y - 25y -775 = 0

⇒ (y+31)(y-25) = 0

⇒ y = -31, 25

as length can not be -ve , so y = 25

then x = 25+30 = 55

Hence the dimensions of the metal piece are 55, 25 inches

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Two cities are 3450 miles apart. A plane leaves one of​ them, traveling towards the other at an average speed of 310 miles per h
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1. In a factory, all employees work a basic week of 38 hours. Any overtime worked during week-days is paid for at time and a hal
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Answer:

Step-by-step explanation:

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2 hrs overtime on sunday: 2 * 3(8.96) = 2 * 26.88 = 53.76

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===============================

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(c) gross wage : 584 + 551.15 = 1135.15 <==

================================

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