Answer:
(1 cm)cos3πt
Step-by-step explanation:
Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft
where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.
Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations = 2 s
So, f = 3/2 s =1.5 /s = 1.5 Hz
Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm
h = Acos2πft
= (1 cm)cos2π(1.5Hz)t
= (1 cm)cos3πt
Answer:
you should try m a t h w a y it would help with math questions
(4/9)/16 = 4/(9*16) = 4/(4*4*9) = 1/(4*9) = 1/36
One counter is
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Answer:
1 1/8 ga / 13.5 mi = .0833 ga / mi
1 / .0833 ga/mi = 12 mi / ga
or .0833 ga/mi * 13.5 mi = 1.25 ga
Answer:
- Define your variable and write your equation: 36 + b + (3b-28) = 180°.
- measure of the second angle: 43°.
- measure of the third angle: 101°
Step-by-step explanation:
a = 36
c = 3b - 28
a + b + c = 180°
a = measure of the first angle
b = measure of the second angle
c = measure of the third angle
then:
1) 36 + b + (3b-28) = 180 ⇒ )Define your variable. Write your equation and solve)
b + 3b + 36 - 28 = 180
4b + 8 = 180
4b = 180 - 8
4b = 172
b = 172/4
2) b = 43° ⇒ measure of the second angle
c = 3b - 28
c = 3*43 - 28
c = 129 - 28
3) c = 101° ⇒ measure of the third angle
Check:
36° + 43° + 101° = 180°
