Answer:
y=4x+1
Step-by-step explanation:
First find the gradient of the straight line
Then substitute the gradient in the formula y=mx+c.
Substitute one of the given coordinates in the line to find the value of c.
After finding the value of c substitute it in the formula but do not write the values of x and y in the formula
Answer:
Step-by-step explanation:
Q1: (x-1) * (x+1) * (x-2) * (x+2)
Q2: x'1 = -1/3, x'2 =2
Q3: i dont get this one sry
1) cscΘ = - 2
=>
1
------ = - 2
sinΘ
=> sinΘ = - 0.5 => Θ is in the third and fourth quadrant
=> Θ = 180° + 30° = 210°
and Θ = 360° + 30° = 330°
2) tan Θ = √3
=> Θ = 60° and Θ = 180° + 60° = 240°
I would personally take the number three and trow it out the window but that's not what we are talking about
Answer:
x^2-3x=4
x^2-3x-4=0
x^2-4x+x-4=0
x(x-4)+1(x-4)=0
(x+1)(x-4)=0
x=-1,4
x- intercepts in the point (-1,0) and (4,0)
Step-by-step explanation:
