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Anastaziya [24]

2 years ago

15

A city has an elevation of -17 meters closer to sea level than a city that has an elevation of -40 meters. Agree or Disagree? Wh

y?

2 answers:

abruzzese [7]2 years ago

6 0

I agree because if your answer is in a negative that means, the number that is closer to zero is the greater number, ex: -23>-56.

12345 [234]2 years ago

6 0

I definitely agree with this

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What is the answer to this question?

forsale [732]

Answer:

c = 83

b = 79

a = 101

d = 97

.

.........................

5 0

2 years ago

Quinn had $4.00 he spent 1/2 of his money on baseball cards,1/4 of it on a drink and 1/8 of it on bubble gum. how much does quin

Anit [1.1K]

He has $.50 left
1/2 on baseball cards = $2.00
1/4 on a drink = $1.00
1/8 on bible gum = $.50
Which adds up to $3.50 so therefore he has 50 cents left

4.00 - 3.50 = .50

6 0

3 years ago

The ratio of roses to carnations is 7 to 5. If 96 flowers are needed for table decorations,

coldgirl [10]

Answer: 56 roses and 40 carnations are needed.

Step-by-step explanation: <u>Here’s the table of ratios that’ll help you find how many roses and carnations are needed to make a total of 96 flowers for table decorations:</u>

7:5 /14:10 /21:15 /28:20 /35:25 /42:30 /49:35/ 56:40/

*56 + 40 = 96

Hence, 56 roses and 40 carnations are needed if 96 flowers are needed for table decorations.

<u></u>

8 0

2 years ago

How does the graph of f(x)=3lx+2l+4 relate to its parent function?

Sergeeva-Olga [200]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units

check the picture below

7 0

3 years ago

I need help on this?!

Sergio039 [100]

If you nee solving it will be:
c^6(-3c^5)^2
c^6(3c^5)^2
c^6·3^2(c^5)^2
c^6·9(c^5)^2
c^6·9c^10
9c^6c^10
9c^6+10
9c^16
So the answer is:
9c^16
(9c to the power of 16)
Sorry I was late..

3 0

3 years ago