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3 years ago

Simplify: 5q^2r (times) 2q^4r^7 -------(fraction bar)---------- 6r^2t^2(times) 4q^3r^3

1 answer:

8 0

I'm not sure this is right, so please don't be mad if I got this completly wrong, but I think this is how you do it. $\frac{ 10q^{6} r^{8} }{ 24r^{5} t^{2} q^{3}}$ next divide $\frac{5}{6} q^{3} r^{3} t^{2}$

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Two angles are complementary. The first angle is 2x degrees. The second angle is (3x +5) degrees. Determine the measure of each

bixtya [17]

Answer:

70 and 110

Step-by-step explanation:

First angle -- 2x

Second angle -- 3x + 5

Therefore,

2x + 3x + 5 = 180

5x = 175

x = 35

Therefore, 2x -- 70

3x + 5 -------------110

Thenks and mark me brainliest :)

8 0

3 years ago

Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?

bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function $f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}$

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for $x=-6$ in the function and simplify the function.

Hence, let us substitute $x=-6$ in the function, we get,

$f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}$

Let us apply the rule $-\left(-a\right)=a$ , we get,

$f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}$

Multiplying the numbers, we get,

$f(-6)=\frac{100}{-10+e^{0.6}}$

The value of $e^{0.6}=1.822$

Substituting the value of $e^{0.6}=1.822$ , we get,

$f(-6)=\frac{100}{-10+1.822}$

Subtracting the denominator, we have,

$f(-6)=\frac{100}{-8.178}$

Dividing, we have,

$f(-6)=-12.228$

Rounding off to the nearest tenth, we have,

$f(-6)=-12.2$

Thus, the value of f(-6) is -12.2

4 0

2 years ago

The value of a house has increased by 5% the house is now valued at £609000 what is the value of the house before the increase?

lutik1710 [3]

Answer:

$Current \ price = 609000\\\\Let \ the \ original \ price \ be = x\\\\\% increase = 5 \% \ of \ x = \frac{5}{100} \times x = \frac{5x}{100}\\\\Price \ after \ increase, current\ price = \frac{5x}{100} + x\\\\$