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ryzh [129]
4 years ago
5

Simplify: −2s − 9 + 7 − 5r use s = 3 and r =

Mathematics
1 answer:
kari74 [83]4 years ago
4 0

-2(3)-9+7-5r

-6-2-5r

-8-5r Answer

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The following square is made
aksik [14]
Answer:
92 inches
explanation:
48•4
7 0
4 years ago
Which of the sets of ordered pairs represents a function? A={(-4, 5), (1, -1), (2, -2), (2, 3)} B = {(2, 2), (3, -2). (9. 3). (9
EastWind [94]

Answer: Neither A or B

Step-by-step explanation: In order for a relation to be a function, a relation can not have the x-values repeat. Y-values can repeat an infinite amount of times but x-values can only repeat 1 time in a given relation. In relation A, you have (2,-2), and (2,3) and relation B, you have (9,3), and (9,-3). You can also graph both of these relations and do a vertical line test with your pencil and see that it would cross more than once.

Hope this helps.

7 0
2 years ago
Read 2 more answers
The diameter of a standard basketball is 9.5 inches. If the basketballs are covered in rubber, what is the minimum amount of rub
Softa [21]

Answer:

The minimum amount of rubber needed is 1,134 square inches

Step-by-step explanation:

we know that

The surface area of a sphere (basketball ) is given by the formula

SA=4\pi r^{2}

we have

r=9.5/2=4.75\ in ----> the radius is half the diameter

\pi=3.14

substitute

SA=4(3.14)(4.75)^{2}=283.385\ in^2

Multiply by 4 (because are four basketballs)

283.385(4)=1,133.54\ in^2

therefore

The minimum amount of rubber needed is 1,134 square inches

6 0
4 years ago
Can you teach me how to do these?? plzaa
Nitella [24]
If we are simplifying, ⅜ ab³a⁴ is
⅜a^5b³. when multiplying like bases you add exponents

second is xy²/2. when dividing like bases you subtract exponents
8 0
3 years ago
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A construction crew wants to hoist a heavy beam so that it is standing up straight. ey tie a rope to the beam, secure the base,
Aliun [14]
Interesting problem ...

The key is to realize that the wires have some distance to the ground, that does not change.

The pole does change. But the vertical height of the pole plus the distance from the pole to the wires is the distance ground to the wires all the time. In other words, for any angle one has:

D = L * sin(alpha) + d, where D is the distance wires-ground, L is the length of the pole, alpha is the angle, and 'd' is the distance from the top of the (inclined) pole to the wires:

L*sin(40) + 8 = L*sin(60) + 2, so one can get the length of the pole:

L = (8-2)/(sin(60) - sin(40)) = 6/0.2232 = 26.88 ft (be careful to have the calculator in degrees not rad)

So the pole is 26.88 ft long!

If the wires are higher than 26.88 ft, no problem. if they are below, the concerns are justified and it won't pass!

Your statement does not mention the distance between the wires and the ground. Do you have it?
4 0
3 years ago
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