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klasskru [66]
3 years ago
5

Please help! geometry problem 3!

Mathematics
1 answer:
Vilka [71]3 years ago
4 0
Comment
|First of all, the triangles are equal by ASA the way the diagram has been marked.

B and E are both right angles.
Side BC = Side DE
<BCA =< EDA 

So triangle BCA = triangle EDA

Now to the letters.
x = y - 1                 Add 1 to both sides.
x + 1 = y                (1)
3x - 2 = 2y + 1       Subtract 1 from both sides.
3x -2 - 1 = 2y
3x - 3 = 2y             Divide by 2
3x/2 - 3/2 = 2y/2
1.5x - 1.5 = y    (2)

Step One
Since (1) and (2) both have y isolated on their respective right sides, they can be equated.

1.5x - 1.5 = x + 1       Take an x from both sides.
0.5x - 1.5 = x - x + 1
0.5x - 1.5 = 1           Add  1.5 to both sides.
0.5x =  1 + 1.5
0.5x = 2.5                 Divide 0.5 on both sides.
0.5x/0.5 = 2.5/0.5

x = 5

Now we need a y value.
x = y - 1 
5 = y - 1 Add 1 to both sides.
5 + 1 = y - 1 + 1
6 = y 

So the 2 sides and the 2 angles are equal when 
x = 5
y = 6

C Answer <<<<<<



 


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Answer:

b. The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0

c. Student's t distribution, as it is a two-sample test for the difference between means.

d. Test statistic t = 5.42.

P-value = 0

e. They appear to be significantly different, as the sample data gives strong evidence that the difference is greater than 0.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the mean life spans in the county is significantly different for whites and nonwhites.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0

The significance level is 0.05.

The sample 1 (white), of size n1=124 has a mean of 45.3 and a standard deviation of 12.7.

The sample 2 (non-white), of size n2=82 has a mean of 34.1 and a standard deviation of 15.6.

The difference between sample means is Md=11.2.

M_d=M_1-M_2=45.3-34.1=11.2

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12.7^2}{124}+\dfrac{15.6^2}{82}}\\\\\\s_{M_d}=\sqrt{1.301+2.968}=\sqrt{4.269}=2.066

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{11.2-0}{2.066}=\dfrac{11.2}{2.066}=5.42

The degrees of freedom for this test are:

df=n_1+n_2-2=124+82-2=204

This test is a two-tailed test, with 204 degrees of freedom and t=5.42, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=2\cdot P(t>5.42)=0.0000002

As the P-value (0.0000002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the mean life spans in the county is significantly different for whites and nonwhites.

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Hi there!

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\large\boxed{z = \frac{x-\mu}{\sigma}}

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Plug in the knowns for both and rearrange to solve for the mean:

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Other given:

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