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mixer [17]
4 years ago
11

Mr Barton was answering the problem below the question

Mathematics
1 answer:
polet [3.4K]4 years ago
4 0
No the student is incorrect the answer is actually 332
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Thanks for your response!<br> Question will be show✔
algol13
<h3>Answer:</h3>

\large\boxed{-1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}}

<h3>Step-by-step explanation:</h3>

In this question, it's asking you to put the numbers that were given from <em>least </em>to <em>greatest.</em>

Our given numbers are:

  • \frac{6}{40}
  • 0.35
  • 1\frac{3}{4}
  • -1\frac{16}{25}

Now, lets sort them out.

We know that negative numbers would be the least. Sicne there's only one negative number, we would put that first because it's the least out of the numbers.

\frac{6}{40} would go next. To make it easier, we can turn it into a decimal. \frac{6}{40} = 0.15 when you divide.

0.35 will go next. This would be bigger than 0.15, but lower than the next number.

1\frac{3}{4} would go last, due to the fact that it's the greatest. 1\frac{3}{4} is the same as 1.75

When you put them in order, you should get -1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
4 0
3 years ago
Re-write the quadratic function below in Standard Form y=-2(x-6)^2-3
Marat540 [252]

Answer:

Step-by-step explanation:

y=−2x2+24x−75

8 0
3 years ago
Simplify the expression and write your answer in<br> scientific notation: (1.9 X 10^5)^3
lord [1]

Answer:

{(1.9 \times  {10}^{5}) }^{3}

open the bracket:

=  {1.9}^{3}  \times  {10}^{(5 \times 3)}  \\  { \boxed{= 6.859 \times  {10}^{15} }}

8 0
3 years ago
Anderia is having a party with 25 people. She has 6 1/2 large pizzas at the party. She gives equal amounts of pizza to each pers
malfutka [58]

Answer:

Everyone got 52/25 = 2.08 slices of pizza.

Step-by-step explanation:

1 large sized pizza = 8 slices

6.5 large sized pizzas = 52 slices

52/25 = 2.08

Hope this helps :D

3 0
3 years ago
Consider the system of equations.
jok3333 [9.3K]

Given:

The system of equations:

x-3y=9

\dfrac{1}{5}x-2y=-1

To find:

The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.

Solution:

We have,

x-3y=9                        ...(i)

\dfrac{1}{5}x-2y=-1       ...(ii)

The coefficient of x in (i) and (ii) are 1 and \dfrac{1}{5} respectively.

To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.

It means, we have to convert \dfrac{1}{5} into -1. It is possible if we multiply the equation (ii) by -5.

On multiplying equation (ii) by -5, we get

-x+10y=5       ...(iii)

On adding (i) and (iii), we get

7y=14

Here, x is eliminated.

Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.

6 0
3 years ago
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