Let A represent the value of the car after each year.
A= initial value (P)×(1+percent increase(r)) ^time
A=P×(1+r)^t
A=18710×(1+(-12%))^8
A=18710×(1-12%)^8
A=18710×(1-0.12)^8
A=18710×(0.88)^8
A= 6728.7619591115
The best approximation is 6729
Therefore the value of the car will be about $6729 after 8 years
Your answer is B.
Answer:
Matha - Jim = 200 feet.
Step-by-step explanation:
<em><u>Jim's distance</u></em>
J = sqrt(w^2 + L^2)
J = sqrt(300^2 + 400^2)
J = sqrt(900 + 1600)
J = sqrt(2500)
J = 500
<em><u>Martha's distance</u></em>
M = 300 + 400
M = 700 Feet
Answer
M - J = 700 - 500 = 200
Jim walks 200 feet less than Martha.
Answer:
Step 4
part a: no answer yet still having trouble showing my work
part b:
-0.125(x-24)^2+50
-0.125(x-24)(x-24)+50
-0.125(x^2-24x-24x+576)+50
-0.125(x^2-48x+576)+50
-0.125x^2+6x-75+50
-0.125x^2+6x-22
a=-0.125
b=6
c=-22
part c: yes he went through
part d:
plug in roots (4,0) and (44,0)
if x is 4 and y is 0
0=-0.125(4)^2+6(4)-22
0=-2+24-22
0=-2+2
0=0
if x=44 and y=0
0=-0.125(44)^2+6(44)-22
0=-242+264-22
0=-242+242
0=0
Answer:
5 seconds
Step-by-step explanation:
In order to find the time when it landed, we will have to find the x-intercepts.
Equation given to us : -16t² + 48t + 160
Let's take the GCD, which is -16.
-16( t² - 3t - 10 )
Factoring what's inside the brackets, we get the x-intercepts.
What multiples to -10 but adds up to -3? The numbers are -5 and 2
-16 ( t - 5 ) ( t - 2 )
X-intercepts are t - 5 and t - 2
Which is 5 and 2 seconds. But one of this is an extraneous solution and that is 2.
If we substitute the value of 2 in the equation, we will not get 0.
During the x-intercept, the x has a value and y is 0. If we substitute 5 ans x. we will get y as 0.
Hence, the answer is 5 seconds.
<span>The table must show:
Time (minutes) number of gallons remaining
X y
0 Yo
1 Yo – 1.5
2 Yo – 2*1.5
3 Yo – 3*1.5
4 Yo – 4*1.5
And the equation will be ; Y = Yo – 1.5 x, where Yo is the initial amount of water in the bathtub.</span>
