Question

11 black balls and 14 white balls are placed in an urn. two balls are then drawn in succession. what is the probability that the second ball drawn is a white ball if the second ball is drawn without replacing the first ball?

Answer 1

11/25(14/24)+14/25(13/24)=
=154/600+182/600=
=336/600=14/25

Answer 2

$|\Omega|=25\cdot24=600\\ |A|=11\cdot14+14\cdot13=154+182=336\\\\ P(A)=\dfrac{336}{600}=\dfrac{14}{25}=56\%$