what i would do is implant some number under 5 for the X's.
Then work it out as if 3 was x so for instance -4(8-3x3)
Answer:
Quantity remaining= 27.5 grams
Step-by-step explanation:
If the initial quantity of the radioactive isotope= 220 grams
And for each half life it will reduce to half of its original quantity
For first half life
Quantity= 220/2
Quantity= 110 grams
Now for the second half life , the quantity to work with will be 110 grams
Second half life
Quantity= 110/2
Quantity= 55 grams
For the third half life , the quantity to work with is 55 grams
Third half life
Quantity= 55/2
Quantity= 27.5 grams
So after 3 half life's of this radioactive isotope, the amount remaining out of 220 = 27.5 grams.
Another simple way to do this
Since half life reduce the isotope by half of its original.
The third half life will reduce it by (1/2)^3= 1/8
So the quantity remaining= 1/8*220
Quantity remaining= 27.5 grams
Answer:
615.8in^3
Step-by-step explanation:
Given data
Radius= 14in
The expression for the area of circle is given as
A= πr^2
Area= 3.142*14^2
Area= 3.142*196
Area= 615.832in^3
Hence the area is 615.8in^3
Answer:
Step-by-step explanation:
2x - 9y = 23
5x - 3y = -12x - 9y = 23we]periyhw[euiorghweuirtg7wuio[ryg
5x - 3y = -12x - 9y = 23
5x - 3y = -12x - 9y = 23
5x - 3y = -1
