The number of ways she can choose a password is 3986236800
<h3>In how many ways can she choose a password?</h3>
The given parameters and the possible selection of characters are:
First and last choices are possibly repeated lowercase letters;
There are 26 lower characters.
Since the characters can be repeated, then we have
First = 26
Last = 26
The second and third positions must be distinct uppercase letters
There are 26 upper characters.
Since the characters are distinct, then we have
Second = 26
Third = 25
The fourth position must be a # , $, or & symbol;
So, we have
Fourth = 3
The next four positions are distinct nonzero digits.
There are 9 nonzero digits.
Since the digits are distinct, then we have
Next = 9, 8, 7, 6
The number of ways she can choose a password is
Ways = First * Second * Third * Fourth * Next * Last
So, we have
Ways = 26 * 26 * 25 * 3 * 9 * 8 * 7 * 6 * 26
Evaluate the product
Ways = 3986236800
Hence, the number of ways she can choose a password is 3986236800
Read more about combination at:
brainly.com/question/11732255
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