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3 years ago

What is the correct answer?

Mathematics

1 answer:

Valentin [98]3 years ago

8 0

Answer:

Square Root of 384

Step-by-step explanation:

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5x + 7 = 2x - 8 can anyone say how to solve please

SCORPION-xisa [38]

Answer:

x = - 5

Step-by-step explanation:

Given

5x + 7 = 2x - 8 ( subtract 2x from both sides )

3x + 7 = - 8 ( subtract 7 from both sides )

3x = - 15 ( divide both sides by 3 )

x = - 5

4 0

2 years ago

144

ahrayia [7]

Answer:

a³b < 0

Step-by-step explanation:

If a > 0 then a³ > 0

and b < 0

then

a³b → + × - → -

that is a³b < 0

8 0

3 years ago

Determinants and matrix <br><img src="https://tex.z-dn.net/?f=%20%7C%20%5Cfrac%7B7%7D%7B4%7D%20%5C%20%5Cfrac%7B9%7D%7B3%7D%20%20

zavuch27 [327]

<h2>>> Answer </h2>

_________

$\ \:$

$\sf{| \frac{7}{4} \frac{9}{3} | = a}$

$\sf \: |a| = ad - bc$

$\sf\: |a| = (7 \times 3) - (9 \times 4)$

$\sf \: |a| = 21 - 36$

$\sf \: |a| = \bold{ \blue{ - 15}}$

3 0

3 years ago

Read 2 more answers

What is the value of (–4)–3?

son4ous [18]

Here you go. Good luck!

7 0

3 years ago

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

3 years ago