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VashaNatasha [74]
4 years ago
7

Jeff collects stones he wants to put an equal number of stones into plastic cups if Jeff can fit 9 stones into a plastic cup how

many plastic cups would he need if he has 57 stones
Mathematics
2 answers:
Inessa [10]4 years ago
8 0
9 stones in each cup and there will be 6 cups with 3 left over
Helen [10]4 years ago
4 0
He would need seven because 9x6=54 but there would be three left you he needs 7 hope that helps
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I WILL MARK YOU BRAINLIEST PLEASE HELP ME FIND THE VALUE OF X
gavmur [86]

Answer:

6.

Step-by-step explanation:

Proportional triangles once again:

24/8=18/x

18*8=144

144/24=6

:)

6 0
3 years ago
Suppose a lab need to need to make 400 liters of 39% acid solution, but the only solutions available to the lab are 20% acid and
Maslowich

Answer:

c + d = 400

0.2c + 0.5d = 156

Step-by-step explanation:

Let

c = number of liters of 20% acid solution

d = number of liters of 50% acid solution.

c + d = 400 (1)

0.2c + 0.5d = 400(0.39)

0.2c + 0.5d = 156 (2)

From (1)

c = 400 - d

Substitute c = 400 - d into (2)

0.2c + 0.5d = 156 (2)

0.2(400 - d) + 0.5d = 156

80 - 0.2d + 0.5d = 156

- 0.2d + 0.5d = 156 - 80

0.3d = 76

d = 76/0.3

d = 253.33 liters

Substitute d = 253.33 into (1)

c + d = 400

c + 253.33 = 400

c = 400 - 253.33

c = 146.67 liters

6 0
3 years ago
Andre drinks 15 ounces of water, which is 3/5 of the bottle. How much does the bottle hold? Use x for the number of ounces the b
ivann1987 [24]

Step-by-step explanation:

15 = 3/5 x = 3x/5

75 = 3x

x = 25 ounces

4 0
3 years ago
If 7m-3=53, what is the value of 11m+2
Anarel [89]
If 7m-3=53, them 7m=53+3
7m = 56, so m = 8.

Plug this into the other equation, 11m+2.
11(8) + 2 = 88 + 2 = 90

3 0
4 years ago
Read 2 more answers
For the function given below, find a formula for the Riemann sum obtained by dividing the interval (0, 3) into n equal subinterv
Viktor [21]

Splitting up [0, 3] into n equally-spaced subintervals of length \Delta x=\frac{3-0}n = \frac3n gives the partition

\left[0, \dfrac3n\right] \cup \left[\dfrac3n, \dfrac6n\right] \cup \left[\dfrac6n, \dfrac9n\right] \cup \cdots \cup \left[\dfrac{3(n-1)}n, 3\right]

where the right endpoint of the i-th subinterval is given by the sequence

r_i = \dfrac{3i}n

for i\in\{1,2,3,\ldots,n\}.

Then the definite integral is given by the infinite Riemann sum

\displaystyle \int_0^3 2x^2 \, dx = \lim_{n\to\infty} \sum_{i=1}^n 2{r_i}^2 \Delta x \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac6n \sum_{i=1}^n \left(\frac{3i}n\right)^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3} \sum_{i=1}^n i^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3}\cdot\frac{n(n+1)(2n+1)}6 = \boxed{18}

8 0
2 years ago
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