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zaharov [31]
3 years ago
14

What is the answer to the problem i am very confused...

Mathematics
1 answer:
musickatia [10]3 years ago
7 0
The time of takeoff of this hovercraft would be 0 seconds, as if you were starting a timer. So, if you plug in 0 for x (unit for seconds) in your equation, it will look like this:

h(0) = -3(0 - 3)² + 108
Parenthesis first
h(0) = -3(-3)² + 108
Exponents next
h(0) = -3(9) + 108
Multiplication
h(0) = -27 + 108
Combine like terms

h(0) = 81: The height of the hovercraft at the time of takeoff is 81 meters!
Hope this helps :)

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This is homework No one is here to help me could you
sertanlavr [38]
B is the correct answer
6 0
3 years ago
Use factoring to solve <br> 3x^2-11x-6=0
Zielflug [23.3K]

Answer:

x = -0.62 and x = 4.29

These values are approximations !

Step-by-step explanation:

You can not use Factoring to solve this equation. Perhaps you did not use the exact notation as in the original question?

Anyway, to solve it, you can still use the ABC formula.

3x²-11x-6=0

a = 3

b =-11

c = -6

x = [11 + √{121 -4(3 *-6)} ]/ 2*3

x = [11 + √{121 -4(-24)} ]/ 6

x = [11 + √{121 + 96} ]/ 6

x = [11 + √{217} ]/ 6

x = 4.29 This is an approximation !

x = [11 - √{121 -4(3 *-6)} ]/ 2*3

x = [11 - √{121 -4(-24)} ]/ 6

x = [11 - √{121 + 96} ]/ 6

x = [11 - √{217} ]/ 6

x = -0.62 This is an approximation !

extra: see the graph.

4 0
3 years ago
israel started to solve a radical equation in this way: square root of x plus 6 − 4 = x square root of x plus 6 − 4 4 = x 4 squa
agasfer [191]

Lets solve our radical equation \sqrt{x+6}-4=x step by step.

Step 1 add 4 to both sides of the equation:

\sqrt{x+6} -4+4=x +4

\sqrt{x} +6=x+4

Step 2 square both sides of the equation:

\sqrt{x+6} =x+4

\sqrt{x+6}^2 =(x+4)^2

x+6=(x+4)^2

Step 3 expand the binomial in the right hand side:

x+6=x^2+8x+16

Step 4 simplify the expression:

0=x^2+8x-x+16-6

x^2+7x+10=0

Step 5 factor the expression:

(x+2)(x+5)=0

Step 6 solve for each factor:

x+2=0 or x+5=0

x=-2 or x=-5

Now we are going to check both solutions in the original equation to prove if they are valid:

For x=-2

\sqrt{x+6}-4=x

\sqrt{-2+6}-4=-2

\sqrt{4}-4=-2

2-4=-2

-2=-2

The solution x=2 is a valid solution of the rational equation \sqrt{x+6}-4=x.

For x=-5

\sqrt{x+6}-4=x

\sqrt{-5+6}-4=-5

\sqrt{1}-4=-5

1-4=-5

-3\neq -5

Since -3 is not equal to -5, the solution x=-5 is not a valid solution of the rational equation \sqrt{x+6}-4=x; therefore, x=-5 is an extraneous solution of the equation.

We can conclude that even all the algebraic procedures of Israel are correct, he did not check for extraneous solutions.

An extraneous solution of an equation is the solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation. Is worth pointing out that extraneous solutions are particularly frequent in rational equation.

8 0
4 years ago
Please help this is URGENT
spin [16.1K]

Answer:

OPTION C: h(x) = x - 3

Step-by-step explanation:

To find the inverse of the function y = x + 3.

Swap 'x' and 'y'.

We get x = y + 3.

Solve for 'y' now.

We get y = x - 3

Therefore, the inverse function becomes h(x) = x - 3.

6 0
3 years ago
Jackson says has an odd number of model cars.he has 6 cars on one shel and 8 cars on another shelf.is jackson correct?explain
grigory [225]
No. It's rather simple, down to addition. Ask yourself, what does 6 + 8 equal? 6 + 8 = 14. Now is this an odd number? No, 14 is an even number.

I hope this helps! If not I'm sorry. 
4 0
3 years ago
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