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s344n2d4d5 [400]
3 years ago
10

I need help on Part B and C on question 2

Mathematics
1 answer:
kap26 [50]3 years ago
3 0

Answer:

The answer to your question is

Part A. Archimedes grades 6 1/4 tests per day

Part B. 8 19/32 days

Part C.  6  26/29 days

Step-by-step explanation:

Part A

Total time = 6 2/5 days

Number of tests = 40 tests

Process

1.- Convert the mixed fraction to improper fraction

                 6 2/5 = (30 + 2) / 5 = 32/5

2.- Divide 40 by 32/5

                40/1  / 32/5   = (40 x 5) / (32 x 1)

                                      = 200 / 32

Simplify

                                        100 / 16 = 50/8 = 25/4

3.- Convert 25/4 to mixed fractions

                                       6      

                                4   25            

                                        1

                   25/4 = 6 1/4

Archimedes grade 6 1/4 tests per day

Part B

15 more tests

Total time = 32/5

Total tests = 40 + 15 = 55

Process

1.- Divide 55 by 32/5

                                  55 / 1  /  32 /5    = (55 x 5) / (32 x 1)

                                                             = 275 / 32

                                                             

2.- Convert 275/32 to a mixed fraction

                                                 8                                  

                                      32   275

                                             256

                                                19

Result    8 19/32 days

Part C

1.- Divide 55 by 7.25

                                         50 / 7.25     =    5000 / 725

                                                  6

                                725    5000

                                        - 4350

                                            650    

Result 6 650/750 = 6  26/29

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5/8 + 3/4 / -2/3- 5/6.
ElenaW [278]

Answer:

-5/16 or -0.3125

Step-by-step explanation:

3 0
2 years ago
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Complete the table for the given rule. Rule: y=3x<br> x y <br> ? 15<br> 10 ?<br> ? 45
miskamm [114]

Answer:

x = 5, 15 y = 30

Step-by-step explanation:

y=3x is the rule, thus you can use it to find all values.

15 = 3x  Divide 15 by 3 in order to isolate the variable

5 = x

y = 3(10)  Multiply 3 by 10 in order to find y

y = 30

45 = 3x  Divide 45 by 3 in order to isolate the variable

15 = x

4 0
3 years ago
Quadratic Formula to solve the equation x^2- 4x = - 7
mylen [45]

roots of the equation x^2- 4x = - 7 are  2+3i and 2-3i

What are the natures of root of quadratic equation?

Case I: 4ac > b^2

The roots of the quadratic equation ax^2 + bx + c = 0are real and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive.

Situation II:  b^2-4ac =0

The roots and of the quadratic equationax^2 + bx + c = 0  are real and equal when a, b, and c are real numbers, a 0, and the discriminant is zero.

Case III: b^2-4ac<0

The quadratic equation ax^2 + bx + c = 0 has roots when a, b, and c are real numbers, a 0, and the discriminant is negative, but these roots are not equal and are not real. We refer to the roots in this instance as fictitious.

Case IV: Perfect square and b^2 - 4ac > 0

The roots of the quadratic equation ax^2 + bx + c = 0  are real, rational, and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive and perfect square.

Quadratic Formula x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}

x^2- 4x = - 7

x^2-4x+7=0

Here a = 1 , b = -4 , c = 7

using quadratic formula

x={\frac {-(-4)\pm {\sqrt {(-4)^{2}-4(1)(7)}}}{2(1)}}

x={\frac {4\pm {\sqrt {-12}}}{2}}

x={\ {2\pm {\ 3i}}

Learn more about quadratic equation from the link below

brainly.com/question/2279540

#SPJ1

8 0
8 months ago
What’s the quotient of 2 divided by 1/3
just olya [345]
2 4/5 divided by 1 1/3
= 14/5 divided by 4/3
= 14/5 * 3/4
= 42/20
= 21/10
= 2 1/10
Final Answer: 2 1/10
7 0
2 years ago
The point A,B,C and D represent the complex number Z1,Z2,Z3 and Z4 and O is the origin. If OABC is a parallelogram, and Z1=1+3i
aleksley [76]

Complex numbers are divided into two parts; real and imaginary parts. The value of Z3 is 5+ 8i

Given that:

Z_1 = 1 + 3i

Z_2 = 4 + 5i

Since O is the origin, then:

C = OA + OB

This means that:

Z_3 = Z_1 + Z_2

So, we have:

Z_3 = 1 + 3i + 4 + 5i

Collect like terms

Z_3 = 1 + 4+ 3i  + 5i

Z_3 = 5+ 8i

Hence, complex number Z3 is 5+ 8i

Read more about complex numbers at:

brainly.com/question/18509723

8 0
2 years ago
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