1*n-10 = (5/6)*n-((1/3)*n)-7 // - (5/6)*n-((1/3)*n)-7

1*n-((5/6)*n)+(1/3)*n-10+7 = 0

n+(-5/6)*n+(1/3)*n-10+7 = 0

1/2*n-3 = 0 // + 3

1/2*n = 3 // : 1/2

n = 3/1/2

n = 6

That's just in case you had to show your work lol^^

3 0

3 years ago

Read 2 more answers

Square root of 18 as a mixed number

Vika [28.1K]

4 1/5 should be your answer

6 0

3 years ago

Pat's Pizza Place sells large pies for $12 with a charge of $2 for each topping. If Reagan only has a $20 bill to spend on a piz

Cerrena [4.2K]

Answer:

The 1st graph

Step-by-step explanation:

20 = 2t + 12

2t = 8

t = 4

At most she can afford 4 toppings which means she can have 4 toppings to less: t ≤ 4. This is represented in the 1st graph.

3 0

3 years ago

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Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su

777dan777 [17]

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

$a, ar, ar^2,...\\a = 7\\r = 7$

$7, 7^2, 7^3, 7^4...$

Sum of n terms in a geometric progression:

$S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}$

For sum of five terms, we put n= 5, a = 7, r = 7

$S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607$

The sum of first five term of GP is 19607.

Verification:

$2801\times 7 = 19607$

Thus, the sum is equal to product of 2801 and 7.

7 0

3 years ago