The length of extra cable that is required to connect the two pieces of existing cable is equal to 182 meters.
<h3>How to determine the length of extra cable?</h3>
In order to determine the length of extra cable that is required to connect the two pieces of existing cable, we would apply the law of cosine as follows:
B² = A² + C² - 2(A)(C)cosB
Substituting the given parameters into the formula, we have;
B² = 325.0² + 430.0² - 2(325.0)(430.0)cos23
B² = 105,625 + 184,900 - 279,500(0.9205)
B² = 290,525 - 257,279.75
B² = 33,245.25
B = √33,245.25
B = 182.33 ≈ 182 meters.
Read more on cosine law here: brainly.com/question/11000638
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Answer:
$980
Nvm you have to multiply 98 by 10 since there are 10 participants. :)
Step-by-step explanation:
Well, first we wanted to find how much the morning classes cost together. You have to $28 multiplied with 75/100. I am multiplying it with 75/100 instead of 25/100 because the discount cuts off the 25% and the 75% is what you still have to pay. This will give you 2100/100 which is $21. Now you have to multiply $21 with 2 since there are two morning classes. $21 x 2 equals $42. Total for Morning Classes is $42.
Now the other two classes don't have a discount. So all you have to do is $28 x 2 or $28 + $28. This gives you $56. Total for The Other Classes is $56.
Last Step:
Total for Morning Classes + Total for the Other Classes = $56 + $42
= $98
Hope that helped! :)
Answer:
Step-by-step explanation:
Surely the units of time: minut, hour, second.
Answer:
Example 0-30 in 0-5 5-10 10-15 etc... upto 25-30
a) 12 and 15 or 10 and 15
b) none
c) none
a) Confidence Level Margin of Error Error Bar
68.3%, sx 12.2857 ±2.275 (±18.52%)
so a0 could be also 12.2857 - 2.275 = 10
Answer therefore may be 10 and 15
So try do a histogram go in 10's across 1-10,10-20,20-30,30-40,40-50
And if mean is 43 then you would need to multiply everything inside box by 0.3 before you can start the y axes
questions like this start with 0 - 50
Answer:what site are you on?
Step-by-step explanation: