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Svet_ta [14]
3 years ago
6

A bag contains nickels, quarters and pennies. If a handful of coins brings in five nickels, 3 quarters, and nine pennies, how mu

ch money is expected to be in the bag if 90 coins are in the bag?
Mathematics
1 answer:
LenKa [72]3 years ago
7 0
An estimated guess of $5.50 but the amount could range anywhere from $1.82 to $18.25
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You are going to play a game where you bet a dollar and get to flip a coin ten (10) times. If you get four (4) heads in a row, y
klio [65]

Answer:

Approximately 4,000 times

Step-by-step explanation:

If you're flipping a coin to get 4 heads out of 10 and you times it by 10,000 then you would have a probable win rate of 4,000.

3 0
3 years ago
A college Statistics class conducted a survey concerning community attitudes about the college's large homecoming celebration. T
gogolik [260]

Answer:

A) Yes

B) No

C) No

D) No

Step-by-step explanation:

A) Yes, every telephone number that could occur in that community will have an equal chance of being generated because the telephone numbers were generated randomly.

B) No, this method of generating telephone numbers would not result in a simple random sample (SRS) of local residences because the first three digits were generated in a different random way than the last four digits.

C) No, this method would not generate an SRS of local voters because not everybody will be pick up when they call because they may not be at home or they may be too busy to pick up.

D) No, this method is not unbiased in generating samples of households because there will be nonresponse bias since not everyone will pick up the call

4 0
3 years ago
Algebra Vocab help? (25 points)
oee [108]
3
6
1
4
2
5

I hope this helps :)
6 0
3 years ago
Pls help fast i dont get this
IrinaVladis [17]
For the first one it is the fourth one 15/x
4 0
3 years ago
Prove the statement holds for all positive integers:<br><br> 2 + 4 + 6 + ... + 2n = n² + n
crimeas [40]

Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.

The relation 2+4+6+...+2n = n^2+n has to be proved.

If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

Assume that the relation holds for any value of n.

2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)

= n^2 + n + 2n + 2

= n^2 + 2n + 1 + n + 1

= (n + 1)^2 + (n + 1)

This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.

<span>By mathematical induction the relation is true for any value of n.</span>

6 0
3 years ago
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