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lawyer [7]
3 years ago
6

Simplify the expression

Mathematics
1 answer:
kow [346]3 years ago
4 0

Answer:

<h3>           f(x) = 5x² + 2x</h3><h3>           g(x) = 6x - 6</h3>

Step-by-step explanation:

\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}\\\\6(x^2-3x+2)\ne0\ \iff\ x=\frac{3\pm\sqrt{9-8}}{2}\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\\\\\\\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}=\dfrac{x(5x^2-8x-4)}{6(x^2-3x+2)}=\dfrac{x(5x^2-10x+2x-4)}{6(x^2-2x-x+2)}=\\\\\\=\dfrac{x[5x(x-2)+2(x-2)]}{6[x(x-2)-(x-2)]} =\dfrac{x(x-2)(5x+2)}{6(x-2)(x-1)}=\dfrac{x(5x+2)}{6(x-1)}=\dfrac{5x^2+2x}{6x-6}\\\\\\f(x)=5x^2+2x\\\\g(x)=6x-6

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If f(x) = x5 â€" 1, g(x) = 5x2, and h(x) = 2x, which expression is equivalent to [g o f o h](9)? 2(5(95 â€" 1)2) 2((5 · 92)5 â€
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The equivalent expression for [gofoh](9) is 5(32(9)^5-1).

According to the given question.

We have three functions

f(x) = x^5 - 1

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h(x) = 2x

Here, we have to find the equivalent expression for [gofoh](9).

so,

gofoh(x)

= g((2x)^5 -1)

= g(32x^5 -1)

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Therefore,

gofoh(9)

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Hence, the equivalent expression for [gofoh](9) is 5(32(9)^5-1).

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a philanthropist deposits 2,000$, in a trust fund that pays 6.0%interest , compunded continuously. The balance given to the coll
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Answer:

$6414

Step-by-step explanation:

Step one

given

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Step two:

The compound interest formula is

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substituting we have

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The amount given to the college is $6414

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