Answer:
18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
Suppose the mean number of deviations and incursions per year at the Los Angeles International Airport (LAX) is 2.
This means that 
Find the probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year
This is P(X = 3).


18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year
Y = x + 13
y + x ≥ 103
x + 13 + x ≥ 103
Inequality is:
2 x + 13 ≥ 103
2 x ≥ 103 - 13
2 x ≥ 90
x ≥ 90 : 2
x ≥ 45
The youngest age Juanita`s cousin can be is 45.
Answer:
C=3.14*32=100.48mm
Step-by-step explanation:
I think it’s SSS but I’m not 100% sure