Can someone solve this?
1 answer:
Answer:
B :
Step-by-step explanation:
If you divide a rhombus using its diagonals, you get 4 right triangles, whose legs are both 1/2 the length of the diagonals.
This means that the legs of one of those 4 triangles have lengths of 2x/2, and 8x/2, so the legs of one of those triangles x and 4x. This makes the length of one side equal to . Because all 4 sides are the same length, you multiply this value by 4, and get
, which is B.
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Consider the absolute value, because we only worry about the quadrant later.
Thus, we know that the hypotenuse has a length of 4 units, and the side opposite the angle, A is √3, because this is the nature of the sine function in relation to its triangular component.
The missing side can be found using Pythagoras' Theorem:
4² - (√3)² = x²
16 - 3 = x²
13 = x²
x = √13
Since angle A is in the third quadrant, the tangent function will produce a positive angle.
Thus, we know that the hypotenuse has a length of 4 units, and the side opposite the angle, A is √3, because this is the nature of the sine function in relation to its triangular component.
The missing side can be found using Pythagoras' Theorem:
4² - (√3)² = x²
16 - 3 = x²
13 = x²
x = √13
Since angle A is in the third quadrant, the tangent function will produce a positive angle.