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Elan Coil [88]
3 years ago
9

Im so bad at math. Help please!

Mathematics
1 answer:
Ulleksa [173]3 years ago
6 0
Answer is C. Granted gas prices are fixed. if you buy 1 gallon.. price is x. if you buy 2 gallons, price is 2x. and so on. constant rate of change.
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Simplify (-3x^2)^2 show work
Feliz [49]

Answer: 9x^4

Using the rules of exponents multiply the -3 times the -3 which equals 9 canceling out the negatives. Then you have that other ^2 but you also had the other one so you still have to keep it which equals that ^4.

6 0
3 years ago
HELPPP!!!
madam [21]

Answer:

2 and a half @ 2.5 inches (sorry i can't type the fraction)

Step-by-step explanation:

  • english is my second language so sorry if you doesn't understand:

(1/2, 1/4)=(x,y)

based on the graph shown that each grid on the y axis represents 1/4, that is the smallest scale stood in the y axis.

this means 2 grid= 1/4 x 2 = 1/2 @ 0.5 inches.

since the '5 months-hair-length' is above about 2 grid above 2 inch:

2 inch + 0.5 inch= 2.5 inch

4 0
3 years ago
Find the total surface area of a cylinder if r=2 and h=8
Ghella [55]

Answer:

100.5

Step-by-step explanation:

22/7*2^2*8

=22/7*4*8

=22/7*32

=100.5

5 0
3 years ago
Please help?
Mazyrski [523]

Answer:

23\sqrt{3}\ un^2

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\

2. Note that

A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

7 0
3 years ago
Tom rode his horse for 4/6 mile. Liz rode her horse for and equal distance. what is an equivalent fraction that describes how fa
Tpy6a [65]
I saw the images that accompanied this problem. 

2 circles: circle 1 has 6 slices ; circle 2 has 3 slices

Circle 1 is for Tom: you can shade 4 slices out of the 6 slices.
Circle 2 is for Liz: you can shade 2 slices out of the 3 slices.

4/6 is equal to 2/3 because when 4 and 6 are both divided by 2, they give quotient of 2 and 3, respectively.

4 ÷ 2 = 2
6 ÷ 2 = 3
 
3 0
3 years ago
Read 2 more answers
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