<span>29 divided by (3/8 + 5/6)
24</span>
4 consecutive integers...z, z + 1, z + 2, z + 3
z + (z + 1) + (z + 2) + (z + 3) = 166...combine like terms
4z + 6 = 166
4z = 166 - 6
4z = 160
z = 160/4
z = 40
z + 1 = 40 + 1 = 41
z + 2 = 40 + 2 = 42
z + 3 = 40 + 3 = 43
so ur numbers are : 40,41,42,43 with the largest being 43
Answer:
Step-by-step explanation: you just need to find the greatest factors and least multiple then do it to two numbers
After consideration I'm not sure but I think x=3 and y=6 I'm not a math whiz but this made sense to me.
