Question

What are the roots of 3x2 + 10 = 4x?

Answer 1

Answer:C

Step-by-step explanation:

Answer 2

Answer:

Option C is correct.

roots of the given equation , $x =\frac{2\pm i\sqrt{26}}{3}$

Step-by-step explanation:

Given the equation: $3x^2+10 = 4x$

We can write this equation as:

$3x^2-4x + 10 =0$

A quadratic equation is in the form of $ax^2+bx+c =0$      ......[1] where a,b ,c are the coefficient and x is the variable,

the solution of the equation is given by;

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing given equation with equation [1] we get;

a = 3 , b = -4 and c =10

So, the solution of the given equation is given by;

$x = \frac{-(-4)\pm\sqrt{(-4)^2-4(3)(10)}}{2(3)}$

or

$x = \frac{4\pm\sqrt{(16-120}}{6} = \frac{4\pm\sqrt{(-104)}}{6} = \frac{4\pm\sqrt{(-4 \times 26)}}{6}$

or

$x =\frac{4\pm2 \sqrt{(-26)}}{6} = \frac{4\pm2 i\sqrt{26}}{6}$    [∴$\sqrt{-1} = i$

Simplify:

$x =\frac{2\pm i\sqrt{26}}{3}$

therefore, the roots of the given equation are; $x =\frac{2\pm i\sqrt{26}}{3}$