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3 years ago

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!

Mathematics

1 answer:

Helen [10]3 years ago

6 0

Answer

<h2>4060 Dollars</h2>

Here's why this is correct

and if Elena gets a base pay of $1,500 per month, then we add 8% of the total sales, ($32,000) and 8% of 32,000 is $2,560.

8% of 32,000 = 2,560

So we add $2,560 by $1,500 and we get 4060 Dollars.

Hope this helps! <3

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A graduate student majoring in linguistics is interested in studying the number of students in her college who are bilingual. Of

Eddi Din [679]

Answer:

48.41% probability that 17 or fewer of them are bilingual.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 50, p = \frac{466}{1320} = 0.3530$

$\mu = E(X) = np = 50*0.3530 = 17.65$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{50*0.3530*0.6470} = 3.38$

Probability that 17 or fewer of them are bilingual.

Using continuity correction, this is $P(X \leq 17 + 0.5) = P(X \leq 17.5)$ , which is the pvalue of Z when X = 17.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17.5 - 17.65}{3.38}$

$Z = -0.04$

$Z = -0.04$ has a pvalue of 0.4841

48.41% probability that 17 or fewer of them are bilingual.

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3 years ago

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