The difference of the given functions is x^2 + 10
<h3>Difference of functions</h3>
Given the following functions
f(x) = 2x^2 + 3 and
g(x)=x^2-7
Take the difference
(f-g)(x) = 2x^2 + 3 - (x^2 - 7)
(f-g)(x) = 2x^2 - x^2 +3 + 7
(f-g)(x) = x^2 + 10
Hence the difference of the given functions is x^2 + 10
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Answer:
The explicit formula is Tn = 18[(2/3)^(n-1)]
Where n is the term we are looking for
Step-by-step explanation:
Here, we want to get an explicit formula to model the equation
Now, F(2) = 2/3 * f1 = 2/3 * 18 = 12
F(3) = 2/3 * f(2) = 2/3 * 12 = 8
F(4) = 2/3 * F(3) = 2/3 * 8 = 16/3
F(5) = 2/3 * 16/3 = 32/9
Thus, seeing how the equations are progressing, we can definitely see a pattern.
That is Tn = (2/3)^(n-1)(18)
I’m trying to put the answer but I won’t let me
Answer:
y = 3x + 3
Step-by-step explanation:
when you check, only that equation delivers the correct x and y pairs.
x = 0, => y = 3×0 + 3 = 3
x = 1, y = 3×1 + 3 = 3+3 = 6
x = 2, y = 3×2 + 3 = 6 + 3 = 9
x = 3, y = 3×3 + 3 = 9 + 3 = 12
it all fits.
Answer:
- 4 < x < 2
Step-by-step explanation:
Given
- 1 < x + 3 < 5 ( subtract 3 from each interval )
- 1 - 3 < x + 3 - 3 < 5 - 3 , that is
- 4 < x < 2
