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Keith_Richards [23]
3 years ago
15

The formula f(x + 1) = Two-thirds(f(x)) defines a geometric sequence where f(1) = 18. Which explicit formula can be used to mode

l the same sequence?
Mathematics
1 answer:
astraxan [27]3 years ago
7 0

Answer:

The explicit formula is Tn = 18[(2/3)^(n-1)]

Where n is the term we are looking for

Step-by-step explanation:

Here, we want to get an explicit formula to model the equation

Now, F(2) = 2/3 * f1 = 2/3 * 18 = 12

F(3) = 2/3 * f(2) = 2/3 * 12 = 8

F(4) = 2/3 * F(3) = 2/3 * 8 = 16/3

F(5) = 2/3 * 16/3 = 32/9

Thus, seeing how the equations are progressing, we can definitely see a pattern.

That is Tn = (2/3)^(n-1)(18)

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3 years ago
How to find the limit of that question
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Factor the numerator using difference of cubes:
a^3 - b^3 = (a-b)(a^2 +ab+b^2)
a = x
b = 2

\frac{x^3 - 8}{x-2} = \frac{(x-2)(x^2 +2x+4)}{x-2} = x^2 +2x+4

Now you can evaluate limit as x=2.
\lim_{x \to 2} (x^2 +2x+4) = 2^2 +2(2)+4 = 12
5 0
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Need help Last weekend, Raul's basketball team played in a
Darina [25.2K]

Answer:

40%

Step-by-step explanation:

First off, 1/5 is equal to 20%. If you're diving something into 5ths, you can do 100 / 5, which is 20. So you know that Raul scored at least 20% of the points. His friend Jake ALSO scores 20% of the teams points, making 20 + 20 = 40%. Therefore, 40% of the teams points were scored by Raul and Jake.

6 0
3 years ago
Uche pumps gasoline at a rate of 18\,\dfrac{\text{L}}{\text{min}}18 min L ​ 18, start fraction, start text, L, end text, divided
Fiesta28 [93]

Answer:

Uche's pumping rate is <u>300 mL/s</u>.

Step-by-step explanation:

Given:

Uche pumps gasoline at a rate of 18 L/min.

Now, to find Uche's pumping rate in mL/s.

The rate at which Uche pumps gasoline = 18 L/min.

So, to get the pumping rate in mL/s we use convert L/min to mL/s by using conversion factor:

<u>1 L/min = 16.6667 mL/s.</u>

18 L/min = 16.6667 × 18 mL/s.

18L/min = 300 mL/s.

Therefore, Uche's pumping rate is 300 mL/s.

8 0
3 years ago
3(x+y)=y if (x y) is a solution to the equation above and y=0 what is the ratio x/y
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3 0
3 years ago
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