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The Expected value of XX is 1.00.
Given that a box contains 8 cameras and that 4 of them are defective and 2 cameras is selected at random with replacement.
The probability distribution of the hypergeometric is as follows:
Where x is the success in the sample of n trails, N represents the total population, n represents the random sample from the total population and M represents the success in the population.
The probability distribution for X is obtained as below:
From the given information, let X be a random variable, that denotes the number of defective cameras following hypergeometric distribution.
Here, M = 4, n=2 and N=8
The probability distribution of X is obtained below:
The probability distribution of X is,
The probability distribution of X when X=0 is
The probability distribution of X when X=1 is
The probability distribution of X when X=2 is
Use E(X)=∑xP(x) to find the expected values of a random variable X.
The expected values of a random variable X is obtained as shown below:
The expected value of X is,
E(X)=∑xP(x-X)
E(X)=[(0×0.21)+(1×0.57)+(2×0.21)]
E(X)=[0+0.57+0.42]
E(X)=0.99≈1
Hence, the binomial probability distribution of XX when X=0 is 0.21, when X=1 is 0.57 and when X=2 is 0.21 and the expected value of XX is 1.00.
Learn about Binomial probability distribution from here brainly.com/question/10559687
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