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ruslelena [56]
3 years ago
11

How do I write 3 1/2 as an improper fraction in three diffrent ways and fast please

Mathematics
2 answers:
Sav [38]3 years ago
5 0
One can be 7/2 ...................
mafiozo [28]3 years ago
4 0
You can write 3 1/2 as an improper fraction as 7/2
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She sold 346+253=599 tickets.
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What is the difference of the fractions? Use the number line to help find the answer.
Vedmedyk [2.9K]

Answer:

-11/20

Step-by-step explanation:

\frac{1}{5} - \frac{3}{4} = \frac{?}{?}

first you want to get a common denominator (number on the bottom)

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now you can subtract the numerators (number on tope) (also don't touch bottom)

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3 0
3 years ago
*Can someone please help me out with this one?*
Talja [164]
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Can someone please help I really need these points
spayn [35]

Given:

Two chords intersect each other inside the circle.

To find:

The value of x.

Solution:

According to intersecting chords theorem, if two chords intersect each other inside the circle, then the product of two segments of one chord is equal to  the product of two segments of second chord.

In the given circle,

AE\times CE=BE\times DE

(3x-11)\times (5x-4)=(x+2)\times (-x+17)

15x^2-12x-55x+44=-x^2+17x-2x+34

15x^2-67x+44+x^2-15x-34=0

16x^2-82x+10=0

Divide both sides by 2.

8x^2-41x+5=0

Splitting the middle term, we get

8x^2-40x-x+5=0

8x(x-5)-1(x-5)=0

(8x-1)(x-5)=0

Using zero product property, we get

(8x-1)=0 or (x-5)=0

x=\dfrac{1}{8} or x=5

For x=\dfrac{1}{8}, the side AE is negative. So, x=\dfrac{1}{8} is not possible.

Therefore, the required solution is x=5.

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3 years ago
What are the zeros of the quadratic function f(x)=8x^2-16x-15
Marina86 [1]


(4 +  \sqrt{46} ) \div 4
(4 -  \sqrt{46} ) \div 4

8 0
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