Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
Dividing (3x^2-2x) by x gives out 3x-2
Answer:
The answer is a
Step-by-step explanation:
have a nice day :)
He can write 2/3 of a page in 1/4 of an hour.
=> He can write 2/3 × 4 = 8/3 = 2 and 2/3 of a page in an hour
Answer: 2 and 2/3 of a page per hour
ok done. Thank to me :>
Cause 6^8 = 1679616 while if 3^5 times 2^3 only = 1944
