<span>The least common multiple of x² – 8x + 12 and x² – x – 2.
by factoring:
∴ </span><span>x² – 8x + 12 = (x-2)(x-6)
</span><span>x² – x – 2 = (x-2)(x+1)
note: the factor (x-2) is common between them take it one time
∴ LCM = (x-2)(x-6)(x+1)
</span>
We know, distributive property: a(b + c) = ab + ac
4(x + 2) = 4x + 8
In short, Your Answer would be Option B
Hope this helps!
2x + 3 = 1 - 4 (calculate)
2x - 3 = -3 (move the constant to the right)
2x = -3 - 3 (calculate)
2x = -6 (divide both sides)
<em>x = -3</em>
No star is higher; they're the same.
y = 10x + 30
Substitute "9x + 40" with y.
Then you get 9x + 40 = 10x + 30.
Get the variables on one side and the numbers on one side.
Basic algebra used here subtract 9x from both sides. Then subtract 30 from both sides and you will get x = 10.
Plug 10 for X into the equation and you will get Y = 130. Try each problem separately and you will get the same answer for both so they're equal, none is higher.
Answer:
and 
Step-by-step explanation:
Here is how I found out the answers, i graphed them on Desmos:
=solid red line
= dotted black line
Hope this helps! Brainliest would be much appreciated! Have a great day! :)
