Question

‼️‼️solve by substitution {-r+T=5 , -2r+T=4. all these problems w work shown (along w the other problems i posted) r due in the morning any help is appreciated!!let me know if u can’t read my writing!

Answer 1

Answer:

#4: (r,t) = (1,6) #5: (x, y) = (-$\frac{1}{2}$,4) #6: (x, y) = (3, 5) #7: (p, r) = (10,$\frac{14}{3}$ )

Step-by-step explanation:

#4:

Solve for t.

t = 5 + r

Substitute the given value of t into equation

-2r + 5 + r = 4

Solve for r

r = 1

substitute the given value of r into equation

t = 5 + 1

solve for t

t = 6

solution is ordered pair (r, t) = (1,6)

#5:

Solve for y.

y = 2 - 4x

Substitute the given value of y into equation

2x - (2- 4x) = -5

Solve for x

x = - $\frac{1}{2}$

substitute the given value of x into equation

y = 2 - 4x (- $\frac{1}{2}$)

solve for y

y = 4

solution is ordered pair (x, y) = (-$\frac{1}{2}$,4)

#6:

Solve for x

x = -12 + 3y

Substitute the given value of x into equation

2 (-12 + 3y) + y = 11

Solve for y

y = 5

substitute the given value of y into equation

x = -12 + 3 x 5

solve for x

x = 3

solution is ordered pair (x, y) = (3, 5)

#7

Solve for r

r = $\frac{14}{3}$

Substitute the given value of  into equation

-2p + 3x $\frac{14}{3}$  = -6

Solve for p

p = 10

solution is ordered pair (p, r) = (10,$\frac{14}{3}$ )