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3 years ago

7

(8a^-9)^-2/3 Can please show me how to get the answer to this problem?

2 answers:

ser-zykov [4K]3 years ago

5 0

Illl subtract all of them together and get my answer

Svetlanka [38]3 years ago

4 0

$8^{- \frac{2}{3} } a^{6}$
$\frac{1}{8} ^{ \frac{2}{3} } a^{6}$
$\frac{1}{4} a^{6}$

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The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c

Anestetic [448]

Answer:

a) The mean is $\mu = 60$

b) The standard deviation is $\sigma = 9$

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when $X = 55.5, Z = -0.5$

So

$Z = \frac{X - \mu}{\sigma}$

$-0.5 = \frac{55.5 - \mu}{\sigma}$

$-0.5\sigma = 55.5 - \mu$

$\mu = 55.5 + 0.5\sigma$

The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when $X = 71.52, Z = 1.28$

So

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{71.52 - \mu}{\sigma}$

$1.28\sigma = 71.52 - \mu$

$\mu = 71.52 - 1.28\sigma$

Since we also have that $\mu = 55.5 + 0.5\sigma$

$55.5 + 0.5\sigma = 71.52 - 1.28\sigma$

$1.78\sigma = 71.52 - 55.5$

$\sigma = \frac{(71.52 - 55.5)}{1.78}$

$\sigma = 9$

$\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60$

Question

The mean is $\mu = 60$

The standard deviation is $\sigma = 9$

6 0

2 years ago

1/2(3/4n+ 9) and 2(12 + 8x) -3(4x -9) i need help with these two

Ghella [55]

I dont know if this is right but the answer to 2(12+8x)-3(4x-9) might be 4x+51?

5 0

3 years ago

Read 2 more answers

(picture)<br>circle the numbers that are divisble by the number given

Dmitry [639]

Answer:

Hope that this helps!!!

3 0

3 years ago

What is the effect in the time required to solve a problem when you double the size of the input from n to 2n, assuming the numb

kobusy [5.1K]

Answer:

Go to this site

https://www.slader.com/discussion/question/what-is-the-effect-in-the-time-required-to-solve-a-problem-when-you-double-the-size-of-the-input-fro/

there should the your answer

Step-by-step explanation:

3 0

3 years ago

Which statements are TRUE? Select all that apply.

musickatia [10]

Answer:

A, B, D are true

Step-by-step explanation:

A) Speed = Distance travelled ÷ time taken

= 112 ÷ 1.75

= 64 miles per hour

True

B) Cost of 6 pens = $7.74

Cost of 1 pen = 7.74 ÷ 6 = $ 1.29

Cost of 7 pens = 1.29 * 7 = $ 9.03

TRUE

C) Speed = 57 miles per hour

4 hour 10 minutes = 250 minutes

Distance traveled in an hour = 57

Distance traveled in 250 minutes = (57* 250) ÷ 60 = 237.50 miles

FALSE

D) Cost of 17 cans = $ 38.59

Cost of 1 can = 38.59 ÷ 17 = $2.27

Cost of 3 cans = 2.27 * 3 = $ 6.81

TRUE

e) Cost of two dozen eggs = $ 8.40

Cost of an egg = 8.40 ÷ 24 = $ 0.35

FALSE

7 0

3 years ago