(picture) circle the numbers that are divisble by the number given

Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!

blagie [28]

Question 4

1) $\overline{BD}$ bisects $\angle ABC$ , $\overline{EF} \perp \overline{AB}$ , and $\overline{EG} \perp \overline{BC}$ (given)

2) $\angle FBE \cong \angle GBE$ (an angle bisector splits an angle into two congruent parts)

3) $\angle BFE$ and $\angle BGE$ are right angles (perpendicular lines form right angles)

4) $\triangle BFE$ and $\triangle BGE$ are right triangles (a triangle with a right angle is a right triangle)

5) $\overline{BE} \cong \overline{BE}$ (reflexive property)

6) $\triangle BFE \cong \triangle BGE$ (HA)

Question 5

1) $\angle AXO$ and $\angle BYO$ are right angles, $\angle A \cong \angle B$ , $O$ is the midpoint of $\overline{AB}$ (given)

2) $\triangle AXO$ and $\triangle BYO$ are right triangles (a triangle with a right angle is a right triangle)

3) $\overline{AO} \cong \overline{OB}$ (a midpoint splits a segment into two congruent parts)

4) $\triangle AXO \cong \triangle BYO$ (HA)

5) $\overline{OX} \cong \overline{OY}$ (CPCTC)

Question 6

1) $\angle B$ and $\angle D$ are right angles, $\overline{AC}$ bisects $\angle BAD$ (given)

2) $\overline{AC} \cong \overline{AC}$ (reflexive property)

3) $\angle BAC \cong \angle CAD$ (an angle bisector splits an angle into two congruent parts)

4) $\triangle BAC$ and $\triangle CAD$ are right triangles (a triangle with a right angle is a right triangle)

5) $\triangle BAC \cong \triangle DCA$ (HA)

6) $\angle BCA \cong \angle DCA$ (CPCTC)

7) $\overline{CA}$ bisects $\angle ACD$ (if a segment splits an angle into two congruent parts, it is an angle bisector)

Question 7

1) $\angle B$ and $\angle C$ are right angles, $\angle 4 \cong \angle 1$ (given)

2) $\triangle BAD$ and $\triangle CAD$ are right triangles (definition of a right triangle)

3) $\angle 1 \cong \angle 3$ (vertical angles are congruent)

4) $\angle 4 \cong \angle 3$ (transitive property of congruence)

5) $\overline{AD} \cong \overline{AD}$ (reflexive property)

6) $\therefore \triangle BAD \cong \triangle CAD$ (HA theorem)

7) $\angle BDA \cong \angle CDA$ (CPCTC)

8) $\therefore \vec{DA}$ bisects $\angle BDC$ (definition of bisector of an angle)

8 0

1 year ago

The length and width or a rectangular courtyard is 40 feet and 30 feet, respectively. In order to make the courtyard larger, an

SpyIntel [72]

Answer:

The new area is 1800feet^2

Step-by-step explanation:

Step one:

Given data

The length and width or a rectangular courtyard is 40 feet and 30 feet

we can calculate the area of the courtyard as

Area= 40*30

Area= 1200 feet^2

when the extra 15 feet is added to the width

the new width is= 30+15= 45feet

The new area is

Area= 40*45

Area= 1800 feet^2

in all the area will increase by 1800-1200= 600feet

5 0

2 years ago

The standard diameter of a golf ball is 42.67 mm. A golf ball factory does quality control on the balls it manufactures. Golf ba

sergiy2304 [10]

THE ANSWER IS A:

This is the function:

f(x)=|42.67-x|.

42.670 -.002 =42.668

42.668 mm to 42.670

Explanation:

Production will be stopped if the difference in diameter is greater than 0.002 mm.

This difference can mean that the golf ball has a diameter more than 0.002 larger than 42.67 mm, or a diameter more than 0.002 smaller than 42.67. This is the reason for using an absolute value function.

Absolute value represents the distance a number is from 0. For this function, we would want only the values where the function is less than 0.002.

4 0

2 years ago

Can someone that's very good at math please help me?

gtnhenbr [62]

Answer:

35 :

t = 6.25 years

(about 6 years 3 months)

Equation:

t = (1/r)(A/P - 1)

Calculation:

First, converting R percent to r a decimal

r = R/100 = 4%/100 = 0.04 per year,

then, solving our equation

t = (1/0.04)((2500/2000) - 1) = 6.25

t = 6.25 years

The time required to get a total amount, principal plus interest, of $2,500.00 from simple interest on a principal of $2,000.00 at an interest rate of 4% per year is 6.25 years (about 6 years 3 months).

36:

The two distances are the same (out and back), so set them equal.

That is done by having a (rate)(time) equal a (rate)(time).

One time is “x” and the other is “4.8-x.”

One rate is 460 and the other is 500.

460 x = 500 (4.8 -x)

460 x = 2400 - 500x

900 x = 2400

x = 2.5 hours for the slower plane.

4.8- x = 2.3 hours for the faster plane.

8 0

2 years ago

Which of the following angles are supplementary to angle a? Select all that apply.

GuDViN [60]

Answer:

c is the supplement angle

3 0

2 years ago

(picture)circle the numbers that are divisble by the number given ​

(picture)circle the numbers that are divisble by the number given