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arsen [322]
3 years ago
15

I need help with 7 and 8

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0
7 .  0.05145631067 the answer to 7

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Which of the equations below could be the equation of this parabola?
Mademuasel [1]

Answer:

Option B: y = -\frac{1}{2} x^2

Step-by-step explanation:

The parabola has its concavity downwards, so we need a function in the model:

y = ax^2 + bx + c

With a negative value of 'a'

The vertex is (0,0), so we have that:

0 = 0a + 0b + c

c = 0

The x-coordinate of the vertex is given by the equation:

x\_vertex = -b/2a

-b/2a = 0

b = 0

So we have a function in the model:

y = ax^2

With a < 0

The only option with this format is B:

y = -\frac{1}{2} x^2

7 0
3 years ago
5t-17.2=16.3<br><br>What is t?<br>PLEASE HELP!
Arte-miy333 [17]

Answer:6.7

Step-by-step explanation:

5t-17.2=16.3

5t=16.3+17.2

5t=33.5

5t/5t=33.5/5

t=6.7

4 0
3 years ago
PLEASE HELP GIVING BRAINLIEST
Alexeev081 [22]

Answer:

(-5-3/2,3+1/2)

(-13/2,7/2)

option A is correct

Step-by-step explanation:

Hope it helps

4 0
3 years ago
Read 2 more answers
What is the area of the composite figure
kati45 [8]

To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!

\boxed{ \sf \: area \: of \: square =side ^{2}  }

  • Side 3 metre

\rm \implies \: area = 3 ^{2}

\rm \implies9

<em>Thus, The area of 1st square is 9m²...</em>

  • The area of second square will be also 9m², because the sides of both squares are equal.

<h3>Now area of the reactangle⤵️</h3>

  • Length = 6m
  • Breadth = 7+3=10m

\sf \: area \: of \: rectangle = length \times breadtg

\tt \dashrightarrow \: area = 10 \times 3

\tt \dashrightarrow \: area = 30m ^{2}

<em>Thus, The area of rectangle is 30m²....</em>

  • Now, Add area of all the figures to get the total area.

\bf \:total \: area = 9 + 9 + 30 \\   \bf= 48m {}^{2}

<h3><em>Therefore, The total area of the composite figure is 48m²...~</em></h3>
8 0
2 years ago
Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0
3 years ago
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