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Pavel [41]
3 years ago
10

The vertices of the feasible region are (choose all that apply)

Mathematics
1 answer:
Anarel [89]3 years ago
5 0

9514 1404 393

Answer:

  (0,0)

  (0,3)

  (3,2)

  (4,0)

Step-by-step explanation:

The feasible region is the doubly-shaded area in the lower left corner of the first quadrant. It is a quadrilateral, so has 4 vertices. Those are the vertices of the feasible region:

  (0,0)

  (0,3)

  (3,2)

  (4,0)

_____

<em>Additional comment</em>

The objective function has positive slope, so the point (4, 0) will maximize it, and the point (0, 3) will minimize it.

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M∠a=(48−x)°m∠b=(9x−38)°m∠c=90°
Fudgin [204]

Answer:

Option C:

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Step-by-step explanation:

Hello!

The sum of all angles in a triangle is 180°.

Add up all the angles and solve for x by setting the equation to 180°.

<h3>Solve for x</h3>
  • ∠a + ∠b + ∠c = 180°
  • (48 - x)° + (9x - 38)° + 90° = 180°
  • 10° + 8x + 90° = 180°
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Now that we solved for x, we can plug it back into each equation to solve for each angle.

<h3>Angle A</h3>
  • 48° - x
  • 48° - 10°
  • 38°
<h3>Angle B</h3>
  • 9x - 38°
  • 9(10°) - 38°
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<h3>Angle C</h3>
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The answer is Option C:

  • m∠a = 38°
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Answer:

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4 0
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