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3 years ago

.Which one of the following is true when ds/dt=3t^2/2s

1 answer:

4 0

1) Given: ds / dt = 3t^2 / 2s

2) Separate variables: 2s ds = 3t^2 dt

3) Integrate both sides:

∫ 2s ds = ∫ 3t^2 dt

s^2 + constant = t^3 + constant

=> s^2 = t^3 + constant

=> s = √ (t^3 + constant)

Answer: option B.

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Two identical number cubes are shown in the picture. The edge length of these number cubes is 3 centimeters. What is the combine

SVEN [57.7K]

Answer:

They are both identical cubes which makes it much easier.

Work out the volume for just one first.

The formula for volume is:

l x w x h

However, since it is a cube, all lengths are the same.

3 x 3 x 3 = 27

Now multiply it by 2 to get the volume of both combined:

27 x 2 = 54.

In short, your answer is 54cm 3

Hope This Helps You!

Good Luck :)

Step-by-step explanation:

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3 years ago

Write a recursive formula for each sequence given or described below.

valentinak56 [21]

Answer:

$a_{n} =a_{n-1} +3000$ and a₁ =30000 for n = 2,3,4,5,6, ......

Step-by-step explanation:

Doug has joined a job with a starting salary of $30000 per year.

Hence, if a₁ is the salary of Doug in the first year, then

a₁ =30000

Now, each year Doug will receive a raise of $3000 in his salary.

Hence, in the 2nd year, his salary(a₂) will become ( a₁ +3000) per year.

Again, in the 3rd year, his salary(a₃) will become ( a₂ +3000) per year.

Therefor, in the similar manner the recursive formula for his salary in each year will be given as $a_{n} =a_{n-1} +3000$ and a₁ =30000 for n = 2,3,4,5,6, ...... {aₙ is the yearly salary of Doug in the nth year} (Answer)

7 0

3 years ago

Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3>Given :-</h3>

The right angled below is formed by 3 squares A, B and C
The area of square B has an area of 144 inches ²
The area of square C has an of 169 inches ²

We have to find the area of square A?

<h3>Let's Begin :- </h3>

The right angled triangle is formed by 3 squares

We have, 

Area of square B is 144 inches²
Area of square C is 169 inches²

We know that,

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

Subsitute the required values,

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

Area of square C = 169 inches

Let the side of square C be y

Subsitute the required values,

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3>Therefore, By using Pythagoras theorem, </h3>

The sum of squares of base and perpendicular height equal to the square of hypotenuse

That is,

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

Here, 

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

Subsitute the required values,

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3>Therefore,</h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

6 0

2 years ago

HELP ME PLZ I DONT UNDERSTAND THIS

Afina-wow [57]

The corporate team building event will cost $18.00 because $2 multiplied by 6 is $12.00 and $1.00 multiplied by 6 is $6.00 and 6 plus twelve is 18 so it would be $18.00

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3 years ago

Last year, Tim rode his bike a total of 50 3/8 miles. This year, he rode his bike a total of 258 3/4 miles. Which of the followi

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Answer:

Step-by-step explanation:

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2 years ago