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Svetradugi [14.3K]

4 years ago

8

A cylindrical container has a radius of 4 inches and a height of 7 inches. to the nearest tenth, what is the volume of the conta

iner?

1 answer:

Dominik [7]4 years ago

6 0

Answer:351.9

Step-by-step explanation:351.9 cm3

V = πr2h

V = π(4)2(7)

V = π(16)(7)

V = 112π

V = 351.858

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Let the width be w, length = 3w and height = 2w

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Find the missing y-coordinate that makes the two triangles congruent. Triangle ABC: A(8,4), B(2,6), C(5, 0) Triangle MNO: M(7,4)

Zolol [24]

Answer:

y = 8

Step-by-step explanation:

Two triangles are said to be congruent if all the three sides and three angles of both triangles are equal.

The distance between two points on the coordinate plane is given as:

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

In triangle ABC:

$|AB|=\sqrt{(2-8)^2+(6-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|AC|=\sqrt{(5-8)^2+(0-4)^2}=5\\\\|BC|=\sqrt{(5-2)^2+(0-6)^2 }=\sqrt{45}$

In triangle MNO:

$|MN|=\sqrt{(1-7)^2+(2-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|MO|=\sqrt{(4-7)^2+(y-4)^2}\\\\|NO|=\sqrt{(4-1)^2+(y-2)^2 }$

Since triangle ABC and triangle MNO are congruent, hence:

|AB| = |MN| = 2√10, |AC| = |MO| = 5, |BC| = |NO| = √45

$|AC|=|MO|=5\\\\\sqrt{(4-7)^2+(y-4)^2}=5\\\\(4-7)^2+(y-4)^2=25\\\\9 +(y-4)^2=25\\\\(y-4)^2=16\\\\square\ root\ of\ both\ sides:\\\\y-4=4\\\\y=4+4\\\\y=8$

Hence O = (4, 8)

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