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3 years ago

6

Am animal shelter provides a bowl with 1.25 liters of water for 3 cats. About how much water will be left after the cats drink t

heir average daily amount of water?

1 answer:

Gemiola [76]3 years ago

7 0

If you have notes refer to them then ask again and see if it makes sense to you any more

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Your statement balance is 600.00 You have an outstanding checks for

pochemuha

Answer:

B

Step-by-step explanation:

600+125+175=900-400(deposit)=500

or

600-125-175-300-200=100+400=500

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3 years ago

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lakkis [162]

I don’t even wanna go get my kids and get to go to work tomorrow so y’all don’t know what I gotta I wanna is the day you got me in my car so I’m going back home to you and get my kids done and then go to take my car to the house I gotta is a way I gotta is a time for I don’t even wanna go get my kids and get to go to work tomorrow so y’all don’t know what I gotta I wanna is the day you got me in my car so I’m going back home to you and get my kids done and then go to take my car to the house I gotta is a way I gotta is a time for

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3 years ago

What is the common factor among xy2 and x2y ?

Nikolay [14]

Answer:

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3 years ago

!!!!!!!!!I AM CRYINGGGG!!!!!! PLZZZZ

andrey2020 [161]

Answer:

-x^2-2x-3

Step-by-step explanation:

Question 1: Just substitute in the values of f(x) and g(x) and simplify!

f(x) - g(x) = 4x^2-5x+3-(5x^2-3x+6)
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f(x)-g(x) = -x^2-2x-3

Tell me if this helps, and if you still need number 2 or if you can do it by yourself! (Hint: substituting also plays a role in question number 2.)

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3 years ago

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$

3 0

3 years ago

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