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Evgen [1.6K]
3 years ago
12

Solve for x and y y=2x+1 y=x-1

Mathematics
1 answer:
aalyn [17]3 years ago
6 0

Answer:

2=x

Step-by-step explanation:

Substitute the

−x−1 for y to get −x−1=−2x+1

Add x to −x and −2x

to get

−1=−1x+1

Subtract 1 from 1 and −1

to get

−2=−1x

Divide both sides by

-1

to get

2=x

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Find the answer pleaseeee...<br><br>-15/9 + 9/4 = ? <br><br>Please find what the question mark is​
SVEN [57.7K]

Answer:

7/12

Step-by-step explanation:

-15/9+9/4

We need to make them have the same denominator:

9x4= 36 so that is our new denominator

-15x4= -60

9x9=81

(Sorry if i dont make sense)

Now we have -60/36+81/36 which is equal to 21/36.

Now we simplify:

21/36=7/12

3 0
3 years ago
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shepuryov [24]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Can someone help me
nignag [31]
The second answer, cause it best shows the equation, but they just moved the numbers around. It is also the only equation with all the same numbers used in the original equation, too
4 0
3 years ago
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Can someone tell me the answer and explanation plz I’ll give brainlist points
MAVERICK [17]

Answer:

5

Step-by-step explanation:

to cancel out the bottom part of the fraction, we multiply by 3. so now we have y+1= 6. we subtract 1, and get y=5

4 0
3 years ago
Homework Jim Thompson! PART 2
BlackZzzverrR [31]

Problem 2

Part (a)

The 3D shape formed when rotating around the y axis forms a pencil tip

The shape formed when rotating around the x axis is a truncated cone turned on its side.

------------

Part (b)

Check out the two diagrams below.

============================================================

Problem 3

Answer: Choice A and Choice C

-----------------------

Explanation:

Think of stacks of coins. Let's say we had 2 stacks of 10 quarters each. The quarters are identical, so they must produce identical volumes. Those sub-volumes then add up to the same volume for each stack. Now imagine one stack is perfectly aligned and the other stack is a bit crooked. Has the volume changed for the crooked stack? No, it hasn't. We're still dealing with the same amount of coins and they yield the same volume.

For more information, check out Cavalieri's Principle.

With all that in mind, this leads us to choice C. If the bases are the same, and so are the heights, then we must be dealing with the same volumes.

On the other hand, if one base is wider (while the heights are still equal) then the wider based block is going to have more volume. This leads us to choice A.

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2 years ago
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