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2 years ago

The coach of a basketball team is trying to pick a

Mathematics

1 answer:

Brrunno [24]2 years ago

6 0

Answer:

He can select 160 different starting teams.

Step-by-step explanation:

He has:

4 point guards

2 shooting guards

4 small forwards

1 power forward

5 centers

This means that

For each point guard, he can select 2 shooting guards.

For each shooting guard, he can select 4 small forwards.

For each small forward, he can select one power forward.

For each power forward, he can select a center.

How many different possible starting teams can he select?

4*2*4*5 = 160

He can select 160 different starting teams.

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3 years ago

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gtnhenbr [62]

Answer:

72 bowls with 12 cups of cream

Step-by-step explanation:

First, I want to point out that the information, “3 pots of soup” is useless. So disregard that.

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3 years ago

I need urgent help with this. please write out the working and the answer thank you

Lelechka [254]

1.   C = ⁵/₉F - 32
9C = 9(⁵/₉F - 32)
  9C = 9(⁵/₉F) - 9(32)
  9C = 5F - 288
- 5F - 5F
  9C - 5F = -288
- 9C   - 9C
-5F = -9C - 288
-5 -5
F = 1⁴/₅C + 57.6

2. $H = w + \frac{50}{m^{2}}$
   $m^{2}(H) = m^{2}(\frac{50}{m^{2}})$
   $Hm^{2} = 50$
   $\frac{Hm^{2}}{H} = \frac{50}{H}$
   $m^{2} = \frac{50}{H}$
   $\sqrt{m^{2}} = \sqrt{\frac{50}{H}}$
   $m = \frac{\sqrt{50}}{\sqrt{H}}$
   $m = \frac{5\sqrt{2}}{\sqrt{H}}$
   $m = \frac{5\sqrt{2}}{\sqrt{H}} * \frac{\sqrt{H}}{\sqrt{H}}$
   $m = \frac{5\sqrt{2H}}{H}$

3. A = 5 + 4√x
- 5 - 5
  A - 5 = 4√x
  (A - 5)² = (4√x)²
  A² - 10A + 25 = 16x
16 16
¹/₆A² - ⁵/₈A + 1⁹/₁₆ = x

4. $A = \frac{b + c}{b}$
   $Ab = b(\frac{b + c}{b})$
   $Ab = b + c$
   $Ab - b = c$
   $b(A) - b(1) = c$
   $b(A - 1) = c$
   $\frac{b(A - 1)}{A - 1} = \frac{c}{A - 1}$
   $b = \frac{c}{A - 1}$

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3 years ago